有 2 筆資料符合您搜尋的條件
X^2+(X/(X+1))^2=3 =>(0-X)^2+(1-1/(X+1))^2=3 =>√((0-X)^2+(1-1/(X+1))^2)=√3 也就是說把題目改成:求一點(X,1/X+1)到(0,1)的距離為√3 =>求一點在Y=(1/(X+1))上到(0,1)之距為√3 =>Y=(1/(X+1)) 解聯立方程式: (X-0)^2+(Y-1)^2 = 3 與 XY+Y=1 =>(X-0)^2+(Y-1)^2 = X^2+Y^2-2Y-2=0 又X=1/Y-1代入上式 得Y^2-2Y-1-2/Y+1/(Y^2)=0 =>Y^2+1/(Y^2) - 2(Y+1/Y) - 1 = 0 =>(Y+...